函数实现借助转为字符串进行反转对比：

def is_palindrome(n):    # n_str = str(n)    # if n_str == n_str[::-1]:    #     return int(n_str)    if str(n) == str(n)[::-1]:        return n# 测试:output = filter(is_palindrome, range(1, 1000))print('1~1000:', list(output))if list(filter(is_palindrome, range(1, 200))) == [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191]:    print('测试成功!')else:    print('测试失败!')