s = math.sqrt(b * b - 4 * a * c)
n1 = (-b + s) / (2 * a)
n2 = (-b - s) / (2 * a)
return n1, n2
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s = math.sqrt(b * b - 4 * a * c)
n1 = (-b + s) / (2 * a)
n2 = (-b - s) / (2 * a)
return n1, n2