第一题
def normalize(name):
return name.capitalize()
L1 = ['adam', 'LISA', 'barT']
L2 = list(map(normalize, L1))
print(L2)
第二题
def prod(L):
def multiply(x,y):
return x*y
return reduce(multiply,L)
print('3 * 5 * 7 * 9 =', prod([3, 5, 7, 9]))
if prod([3, 5, 7, 9]) == 945:
print('测试成功!')
else:
print('测试失败!')
第三题
from functools import reduce
def str2float(s):
int,float=s.split(".")
def fn(x,y):
return x*10+y
def char(s):
DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
return DIGITS[s]
a=reduce(fn,map(char,int))
b=reduce(fn,map(char,float))
return a+b*(0.1**(len(float)))
print('str2float(\'123.456\') =', str2float('123.456'))
if abs(str2float('123.456') - 123.456) < 0.00001:
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湖与海海
第一题
def normalize(name):
return name.capitalize()
L1 = ['adam', 'LISA', 'barT']
L2 = list(map(normalize, L1))
print(L2)
第二题
def prod(L):
def multiply(x,y):
return x*y
return reduce(multiply,L)
print('3 * 5 * 7 * 9 =', prod([3, 5, 7, 9]))
if prod([3, 5, 7, 9]) == 945:
print('测试成功!')
else:
print('测试失败!')
第三题
from functools import reduce
def str2float(s):
int,float=s.split(".")
def fn(x,y):
return x*10+y
def char(s):
DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
return DIGITS[s]
a=reduce(fn,map(char,int))
b=reduce(fn,map(char,float))
return a+b*(0.1**(len(float)))
print('str2float(\'123.456\') =', str2float('123.456'))
if abs(str2float('123.456') - 123.456) < 0.00001:
print('测试成功!')
else:
print('测试失败!')