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来交作业了

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# 判断回数def is_palindrome(n):
    num = []
    before = n
    later = 0    while n != 0:
        num.append(n % 10)
        n = n // 10    for i in num:
        later = later * 10 + i

    return before == later

不如评论区大佬直接转字符串方便


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