#思路是把123变为321，先通过除法把每一位数字确定，再通过乘法放到对应位置上，最后判断两者是否相等

def is_palindrome(n):

    origin = n

    length = len(str(n))

    result = 0

    while length > 0:

        yushu = n % 10

        n = n // 10

        length = length - 1

        result = result + yushu * (10 ** length)

    return origin == result