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第三题借鉴评论区大佬的答案后得到很清晰的逻辑

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岁羽谌谌

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from functools import reduce

from cv2 import split

num_dict = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}

def char2num(s):

    return num_dict[s]

def str2float(s):

    s1,s2=s.split('.')

    xz=reduce(lambda x,y:10*x+y,map(char2num,s1))

    xf=(reduce(lambda x,y:10*x+y,map(char2num,s2))/(10**len(s2)))

    x=xz+xf

    return x

str2float('123.456')


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