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打卡—切片反向遍历

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def is_palindrome(n):

    num = str(n)

    return num == num[::-1]

射线恶魔

#2 Created at ... [Delete] [Delete and Lock User]

卧槽妙啊

岁羽谌谌

#3 Created at ... [Delete] [Delete and Lock User]

太妙了吧


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