Discuss / Python / 一直学习中

一直学习中

Topic source

job

#1 Created at ... [Delete] [Delete and Lock User]

def is_palindrome(n):

    num = str(n)

    if list(num) == list(reversed(num)):

        return True

res = list(filter(is_palindrome, range(1, 100)))


  • 1

Reply