Discuss / JavaScript / 就这样

就这样

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~曉瘋~

#1 Created at ... [Delete] [Delete and Lock User]

第一题:

var re = /^[\w\.]+@\w+\.\w+$/;

第二题:

var re = /^<([a-zA-Z\s]+)>\s+([\w\.]+@\w+\.\w+)$/;


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